[enkeivette]

You let Sean beat you Ben?! Don't feel bad, he does have a blower. So Sean did manage to pull off a 12.5? Why are you guys still giving him shit?

12 second car, 12 second driver. Thumbs up for Daddy.

[Vettezuki]

Originally Posted by Throttle Crazy

The intersection of hp and torque can still meet at 5250 rpm but be higher numbers.

Will ALWAYS intersect at 5250. It's a "magic" number. Go to How Stuff Works if you want to know the full derivation for it.

[BADDASSC6]

Originally Posted by enkeivette

That's not a shift, that's an expansion or a change. A shift denotes moving the exact curve either up or down the rpm axis.

Sounds like that first semester of LAW SCHOOL again.

[enkeivette]

Originally Posted by BADDASSC6

Sounds like that first semester of LAW SCHOOL again.

Why does everyone think that I'm in my first year? First year was sooo last year ago!!!

[enkeivette]

Originally Posted by Vettezuki

Will ALWAYS intersect at 5250. It's a "magic" number. Go to How Stuff Works if you want to know the full derivation for it.

Motorgen.com is a better source for info, don't go anywhere.

HP is a mathematical calculation from measured torque, which is actually what a dyno measures. It always crosses at about 5250 because of the math equation.

[Vettezuki]

Originally Posted by enkeivette

Motorgen.com is a better source for info, don't go anywhere.

HP is a mathematical calculation from measured torque, which is actually what a dyno measures. It always crosses at about 5250 because of the math equation.

Uhh, 5250 is used in the equation, not because of the math equation. And to be extra annoying, it's actually 5252, derived thusly.

The constant 5252 comes from (33,000 ft·lbf/min)/(2π rad./rev.).

NOTE: The 33,000 ft.lbf/min. is the definition of one HP. Why it's divided by 2π rad./rev. I don't recall. But that's the constant you use.

HP = T[ft.lbf.] x RPM/5252

[Throttle Crazy]

Originally Posted by Vettezuki

Uhh, 5250 is used in the equation, not because of the math equation. And to be extra annoying, it's actually 5252, derived thusly.

The constant 5252 comes from (33,000 ft·lbf/min)/(2π rad./rev.).

NOTE: The 33,000 ft.lbf/min. is the definition of one HP. Why it's divided by 2π rad./rev. I don't recall. But that's the constant you use.

HP = T[ft.lbf.] x RPM/5252

I did mention about the 5252 a couple pages ago. The average horse could lift a 550 pound weight one foot in one second, thereby performing work at the rate of 550 foot pounds per second, or 33,000 foot pounds per minute, for an eight hour shift. That is where the 33,000 ft. lb per minute came from. 550*60= 33,000.

(2π rad./rev.). converts radians to revolutions. There are 2 pi (3.14) or 6.28 radians to 1 rev.

[enkeivette]

That's why I said about 5250.

Are you really trying to say that they cross at about 5250 because it is a number used in the equation but the crossing at 5252 is not a result of that same equation? Ummm.

[Vettezuki]

Originally Posted by enkeivette

That's why I said about 5250.

Are you really trying to say that they cross at about 5250 because it is a number used in the equation but the crossing at 5252 is not a result of that same equation? Ummm.

The correct number is 5252. And yeah, the use of a constant in an equation is not a function of the use of itself in said equation. Are we talking about the same thing?

[enkeivette]

Originally Posted by Vettezuki

The correct number is 5252. And yeah, the use of a constant in an equation is not a function of the use of itself in said equation. Are we talking about the same thing?

True, but the function of this specific equation always yields this specific result (crossing at 5252) does it not?

So would it be wrong to say that they cross at 5252 because of the equation? (The equation which includes all constants and all functions)